Find the Third Term ((2^(n-1))/4)

$(\frac{2^{n - 1}}{4})$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{3} = \frac{2^{(3) - 1}}{4}$

Step 2

Remove parentheses.

$a_{3} = \frac{2^{(3) - 1}}{4}$

Step 3

Simplify the numerator.

Subtract $1$ from $3$ .

$a_{3} = \frac{2^{2}}{4}$

Raise $2$ to the power of $2$ .

$a_{3} = \frac{4}{4}$

Step 4

Divide $4$ by $4$ .

$a_{3} = 1$