Find the Third Term a_n=1/4(2)^(n-1)

$a_{n} = \frac{1}{4} {(2)}^{n - 1}$

Substitute in the value of $n$ to find the $n$ th term.

$a_{3} = \frac{1}{4} \cdot {(2)}^{(3) - 1}$

Simplify the expression.

Subtract $1$ from $3$ .

$a_{3} = \frac{1}{4} \cdot 2^{2}$

Raise $2$ to the power of $2$ .

$a_{3} = \frac{1}{4} \cdot 4$

Cancel the common factor of $4$ .

Cancel the common factor.

$a_{3} = \frac{1}{4} \cdot 4$

Rewrite the expression.

$a_{3} = 1$