Find the Third Term A_n=n(n-1)(n-2)

$A_{n} = n (n - 1) (n - 2)$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$A_{3} = (3) ((3) - 1) ((3) - 2)$

Step 2

Subtract $1$ from $3$ .

$A_{3} = 3 \cdot (2 ((3) - 2))$

Step 3

Multiply $3$ by $2$ .

$A_{3} = 6 ((3) - 2)$

Step 4

Subtract $2$ from $3$ .

$A_{3} = 6 \cdot 1$

Step 5

Multiply $6$ by $1$ .

$A_{3} = 6$