Find the Vertex 1-(x-2)^2

$1 - {(x - 2)}^{2}$

Step 1

Reorder $1$ and $- {(x - 2)}^{2}$ .

$y = - {(x - 2)}^{2} + 1$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = 2$

$k = 1$

Step 3

Find the vertex $(h, k)$ .

$(2, 1)$

Step 4