Find the Vertex 16-(x-1)^2

$16 - {(x - 1)}^{2}$

Step 1

Reorder $16$ and $- {(x - 1)}^{2}$ .

$y = - {(x - 1)}^{2} + 16$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = 1$

$k = 16$

Step 3

Find the vertex $(h, k)$ .

$(1, 16)$

Step 4