Find the Vertex 2x^2+6x+6

$2 x^{2} + 6 x + 6$

Step 1

Rewrite the equation in vertex form.

Complete the square for $2 x^{2} + 6 x + 6$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 2$

$b = 6$

$c = 6$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{6}{2 \cdot 2}$

Cancel the common factor of $6$ and $2$ .

Factor $2$ out of $6$ .

$d = \frac{2 \cdot 3}{2 \cdot 2}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 2$ .

$d = \frac{2 \cdot 3}{2 (2)}$

Cancel the common factor.

$d = \frac{2 \cdot 3}{2 \cdot 2}$

Rewrite the expression.

$d = \frac{3}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 6 - \frac{6^{2}}{4 \cdot 2}$

Simplify the right side.

Simplify each term.

Raise $6$ to the power of $2$ .

$e = 6 - \frac{36}{4 \cdot 2}$

Multiply $4$ by $2$ .

$e = 6 - \frac{36}{8}$

Cancel the common factor of $36$ and $8$ .

Factor $4$ out of $36$ .

$e = 6 - \frac{4 (9)}{8}$

Cancel the common factors.

Factor $4$ out of $8$ .

$e = 6 - \frac{4 \cdot 9}{4 \cdot 2}$

Cancel the common factor.

$e = 6 - \frac{4 \cdot 9}{4 \cdot 2}$

Rewrite the expression.

$e = 6 - \frac{9}{2}$

To write $6$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$e = 6 \cdot \frac{2}{2} - \frac{9}{2}$

Combine $6$ and $\frac{2}{2}$ .

$e = \frac{6 \cdot 2}{2} - \frac{9}{2}$

Combine the numerators over the common denominator.

$e = \frac{6 \cdot 2 - 9}{2}$

Simplify the numerator.

Multiply $6$ by $2$ .

$e = \frac{12 - 9}{2}$

Subtract $9$ from $12$ .

$e = \frac{3}{2}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $2 {(x + \frac{3}{2})}^{2} + \frac{3}{2}$ .

$2 {(x + \frac{3}{2})}^{2} + \frac{3}{2}$

Set $y$ equal to the new right side.

$y = 2 {(x + \frac{3}{2})}^{2} + \frac{3}{2}$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 2$

$h = - \frac{3}{2}$

$k = \frac{3}{2}$

Step 3

Find the vertex $(h, k)$ .

$(- \frac{3}{2}, \frac{3}{2})$

Step 4

Find the Vertex 2x^2+6x+6

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