Find the Vertex f(x)=4-(x-1)^2

$f (x) = 4 - {(x - 1)}^{2}$

Step 1

Reorder $4$ and $- {(x - 1)}^{2}$ .

$y = - {(x - 1)}^{2} + 4$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = 1$

$k = 4$

Step 3

Find the vertex $(h, k)$ .

$(1, 4)$

Step 4