Find the Vertex Form 2x^2-20x+53

$2 x^{2} - 20 x + 53$

Step 1

Write $2 x^{2} - 20 x + 53$ as an equation.

$y = 2 x^{2} - 20 x + 53$

Step 2

Complete the square for $2 x^{2} - 20 x + 53$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 2$

$b = - 20$

$c = 53$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 20}{2 \cdot 2}$

Simplify the right side.

Cancel the common factor of $- 20$ and $2$ .

Factor $2$ out of $- 20$ .

$d = \frac{2 \cdot - 10}{2 \cdot 2}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 2$ .

$d = \frac{2 \cdot - 10}{2 (2)}$

Cancel the common factor.

$d = \frac{2 \cdot - 10}{2 \cdot 2}$

Rewrite the expression.

$d = \frac{- 10}{2}$

Cancel the common factor of $- 10$ and $2$ .

Factor $2$ out of $- 10$ .

$d = \frac{2 \cdot - 5}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$d = \frac{2 \cdot - 5}{2 (1)}$

Cancel the common factor.

$d = \frac{2 \cdot - 5}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{- 5}{1}$

Divide $- 5$ by $1$ .

$d = - 5$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 53 - \frac{{(- 20)}^{2}}{4 \cdot 2}$

Simplify the right side.

Simplify each term.

Raise $- 20$ to the power of $2$ .

$e = 53 - \frac{400}{4 \cdot 2}$

Multiply $4$ by $2$ .

$e = 53 - \frac{400}{8}$

Divide $400$ by $8$ .

$e = 53 - 1 \cdot 50$

Multiply $- 1$ by $50$ .

$e = 53 - 50$

Subtract $50$ from $53$ .

$e = 3$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $2 {(x - 5)}^{2} + 3$ .

$2 {(x - 5)}^{2} + 3$

Step 3

Set $y$ equal to the new right side.

$y = 2 {(x - 5)}^{2} + 3$

Find the Vertex Form 2x^2-20x+53

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