Find the Vertex Form 30x^2+10y^2=300

$30 x^{2} + 10 y^{2} = 300$

Step 1

Divide each term by $300$ to make the right side equal to one.

$\frac{30 x^{2}}{300} + \frac{10 y^{2}}{300} = \frac{300}{300}$

Step 2

Simplify each term in the equation in order to set the right side equal to $1$ . The standard form of an ellipse or hyperbola requires the right side of the equation be $1$ .

$\frac{x^{2}}{10} + \frac{y^{2}}{30} = 1$

Find the Vertex Form 30x^2+10y^2=300

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