Find the Vertex Form -4x^2-16x-14

$- 4 x^{2} - 16 x - 14$

Step 1

Write $- 4 x^{2} - 16 x - 14$ as an equation.

$y = - 4 x^{2} - 16 x - 14$

Step 2

Complete the square for $- 4 x^{2} - 16 x - 14$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 4$

$b = - 16$

$c = - 14$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 16}{2 \cdot - 4}$

Simplify the right side.

Cancel the common factor of $- 16$ and $2$ .

Factor $2$ out of $- 16$ .

$d = \frac{2 \cdot - 8}{2 \cdot - 4}$

Cancel the common factors.

Factor $2$ out of $2 \cdot - 4$ .

$d = \frac{2 \cdot - 8}{2 (- 4)}$

Cancel the common factor.

$d = \frac{2 \cdot - 8}{2 \cdot - 4}$

Rewrite the expression.

$d = \frac{- 8}{- 4}$

Cancel the common factor of $- 8$ and $- 4$ .

Factor $- 4$ out of $- 8$ .

$d = \frac{- 4 (2)}{- 4}$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$d = \frac{- 4 \cdot 2}{- 4 \cdot 1}$

Cancel the common factor.

$d = \frac{- 4 \cdot 2}{- 4 \cdot 1}$

Rewrite the expression.

$d = \frac{2}{1}$

Divide $2$ by $1$ .

$d = 2$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 14 - \frac{{(- 16)}^{2}}{4 \cdot - 4}$

Simplify the right side.

Simplify each term.

Raise $- 16$ to the power of $2$ .

$e = - 14 - \frac{256}{4 \cdot - 4}$

Multiply $4$ by $- 4$ .

$e = - 14 - \frac{256}{- 16}$

Divide $256$ by $- 16$ .

$e = - 14 - - 16$

Multiply $- 1$ by $- 16$ .

$e = - 14 + 16$

Add $- 14$ and $16$ .

$e = 2$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- 4 {(x + 2)}^{2} + 2$ .

$- 4 {(x + 2)}^{2} + 2$

Step 3

Set $y$ equal to the new right side.

$y = - 4 {(x + 2)}^{2} + 2$

Find the Vertex Form -4x^2-16x-14

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