Find the Vertex Form f(x)=4x^2-40x+107

$f (x) = 4 x^{2} - 40 x + 107$

Step 1

Write $f (x) = 4 x^{2} - 40 x + 107$ as an equation.

$y = 4 x^{2} - 40 x + 107$

Step 2

Complete the square for $4 x^{2} - 40 x + 107$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 4$

$b = - 40$

$c = 107$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 40}{2 \cdot 4}$

Simplify the right side.

Cancel the common factor of $- 40$ and $2$ .

Factor $2$ out of $- 40$ .

$d = \frac{2 \cdot - 20}{2 \cdot 4}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 4$ .

$d = \frac{2 \cdot - 20}{2 (4)}$

Cancel the common factor.

$d = \frac{2 \cdot - 20}{2 \cdot 4}$

Rewrite the expression.

$d = \frac{- 20}{4}$

Cancel the common factor of $- 20$ and $4$ .

Factor $4$ out of $- 20$ .

$d = \frac{4 \cdot - 5}{4}$

Cancel the common factors.

Factor $4$ out of $4$ .

$d = \frac{4 \cdot - 5}{4 (1)}$

Cancel the common factor.

$d = \frac{4 \cdot - 5}{4 \cdot 1}$

Rewrite the expression.

$d = \frac{- 5}{1}$

Divide $- 5$ by $1$ .

$d = - 5$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 107 - \frac{{(- 40)}^{2}}{4 \cdot 4}$

Simplify the right side.

Simplify each term.

Raise $- 40$ to the power of $2$ .

$e = 107 - \frac{1600}{4 \cdot 4}$

Multiply $4$ by $4$ .

$e = 107 - \frac{1600}{16}$

Divide $1600$ by $16$ .

$e = 107 - 1 \cdot 100$

Multiply $- 1$ by $100$ .

$e = 107 - 100$

Subtract $100$ from $107$ .

$e = 7$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $4 {(x - 5)}^{2} + 7$ .

$4 {(x - 5)}^{2} + 7$

Step 3

Set $y$ equal to the new right side.

$y = 4 {(x - 5)}^{2} + 7$

Find the Vertex Form f(x)=4x^2-40x+107

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