Find the Vertex Form p(x)=-x^2-3x+3

$p (x) = - x^{2} - 3 x + 3$

Step 1

Write $p (x) = - x^{2} - 3 x + 3$ as an equation.

$y = - x^{2} - 3 x + 3$

Step 2

Complete the square for $- x^{2} - 3 x + 3$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 1$

$b = - 3$

$c = 3$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 3}{2 \cdot - 1}$

Simplify the right side.

Multiply $2$ by $- 1$ .

$d = \frac{- 3}{- 2}$

Dividing two negative values results in a positive value.

$d = \frac{3}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 3 - \frac{{(- 3)}^{2}}{4 \cdot - 1}$

Simplify the right side.

Simplify each term.

Raise $- 3$ to the power of $2$ .

$e = 3 - \frac{9}{4 \cdot - 1}$

Multiply $4$ by $- 1$ .

$e = 3 - \frac{9}{- 4}$

Move the negative in front of the fraction.

$e = 3 - - \frac{9}{4}$

Multiply $- - \frac{9}{4}$ .

Multiply $- 1$ by $- 1$ .

$e = 3 + 1 (\frac{9}{4})$

Multiply $\frac{9}{4}$ by $1$ .

$e = 3 + \frac{9}{4}$

To write $3$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$e = 3 \cdot \frac{4}{4} + \frac{9}{4}$

Combine $3$ and $\frac{4}{4}$ .

$e = \frac{3 \cdot 4}{4} + \frac{9}{4}$

Combine the numerators over the common denominator.

$e = \frac{3 \cdot 4 + 9}{4}$

Simplify the numerator.

Multiply $3$ by $4$ .

$e = \frac{12 + 9}{4}$

Add $12$ and $9$ .

$e = \frac{21}{4}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- {(x + \frac{3}{2})}^{2} + \frac{21}{4}$ .

$- {(x + \frac{3}{2})}^{2} + \frac{21}{4}$

Step 3

Set $y$ equal to the new right side.

$y = - {(x + \frac{3}{2})}^{2} + \frac{21}{4}$

Find the Vertex Form p(x)=-x^2-3x+3

Related Questions

Support LCMGCF.com by disabling your adblocker.