Find the Vertex Form -(x-3)(x+3)

$- (x - 3) (x + 3)$

Step 1

Write $- (x - 3) (x + 3)$ as an equation.

$y = - (x - 3) (x + 3)$

Step 2

Complete the square for $- (x - 3) (x + 3)$ .

Simplify the expression.

Apply the distributive property.

$(- x - - 3) (x + 3)$

Multiply $- 1$ by $- 3$ .

$(- x + 3) (x + 3)$

Expand $(- x + 3) (x + 3)$ using the FOIL Method.

Apply the distributive property.

$- x (x + 3) + 3 (x + 3)$

Apply the distributive property.

$- x \cdot x - x \cdot 3 + 3 (x + 3)$

Apply the distributive property.

$- x \cdot x - x \cdot 3 + 3 x + 3 \cdot 3$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$- (x \cdot x) - x \cdot 3 + 3 x + 3 \cdot 3$

Multiply $x$ by $x$ .

$- x^{2} - x \cdot 3 + 3 x + 3 \cdot 3$

Multiply $3$ by $- 1$ .

$- x^{2} - 3 x + 3 x + 3 \cdot 3$

Multiply $3$ by $3$ .

$- x^{2} - 3 x + 3 x + 9$

Add $- 3 x$ and $3 x$ .

$- x^{2} + 0 + 9$

Add $- x^{2}$ and $0$ .

$- x^{2} + 9$

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 1$

$b = 0$

$c = 9$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 \cdot - 1}$

Simplify the right side.

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 \cdot - 1}$

Move the negative one from the denominator of $\frac{0}{- 1}$ .

$d = - 1 \cdot 0$

Rewrite $- 1 \cdot 0$ as $- 0$ .

$d = - 0$

Multiply $- 1$ by $0$ .

$d = 0$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 9 - \frac{0^{2}}{4 \cdot - 1}$

Simplify the right side.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$e = 9 - \frac{0}{4 \cdot - 1}$

Multiply $4$ by $- 1$ .

$e = 9 - \frac{0}{- 4}$

Divide $0$ by $- 4$ .

$e = 9 - 0$

Multiply $- 1$ by $0$ .

$e = 9 + 0$

Add $9$ and $0$ .

$e = 9$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- {(x + 0)}^{2} + 9$ .

$- {(x + 0)}^{2} + 9$

Step 3

Set $y$ equal to the new right side.

$y = - {(x + 0)}^{2} + 9$

Find the Vertex Form -(x-3)(x+3)

Related Questions

Support LCMGCF.com by disabling your adblocker.