Find the Vertex Form y^2+4x-14y=-53

$y^{2} + 4 x - 14 y = - 53$

Step 1

Isolate $x$ to the left side of the equation.

Move all terms not containing $x$ to the right side of the equation.

Subtract $y^{2}$ from both sides of the equation.

$4 x - 14 y = - 53 - y^{2}$

Add $14 y$ to both sides of the equation.

$4 x = - 53 - y^{2} + 14 y$

Divide each term in $4 x = - 53 - y^{2} + 14 y$ by $4$ and simplify.

Divide each term in $4 x = - 53 - y^{2} + 14 y$ by $4$ .

$\frac{4 x}{4} = \frac{- 53}{4} + \frac{- y^{2}}{4} + \frac{14 y}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 53}{4} + \frac{- y^{2}}{4} + \frac{14 y}{4}$

Divide $x$ by $1$ .

$x = \frac{- 53}{4} + \frac{- y^{2}}{4} + \frac{14 y}{4}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$x = - \frac{53}{4} + \frac{- y^{2}}{4} + \frac{14 y}{4}$

Move the negative in front of the fraction.

$x = - \frac{53}{4} - \frac{y^{2}}{4} + \frac{14 y}{4}$

Cancel the common factor of $14$ and $4$ .

Factor $2$ out of $14 y$ .

$x = - \frac{53}{4} - \frac{y^{2}}{4} + \frac{2 (7 y)}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x = - \frac{53}{4} - \frac{y^{2}}{4} + \frac{2 (7 y)}{2 (2)}$

Cancel the common factor.

$x = - \frac{53}{4} - \frac{y^{2}}{4} + \frac{2 (7 y)}{2 \cdot 2}$

Rewrite the expression.

$x = - \frac{53}{4} - \frac{y^{2}}{4} + \frac{7 y}{2}$

Step 2

Complete the square for $- \frac{53}{4} - \frac{y^{2}}{4} + \frac{7 y}{2}$ .

Move $- \frac{53}{4}$ .

$- \frac{y^{2}}{4} + \frac{7 y}{2} - \frac{53}{4}$

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - \frac{1}{4}$

$b = \frac{7}{2}$

$c = - \frac{53}{4}$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{\frac{7}{2}}{2 (- \frac{1}{4})}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$d = \frac{7}{2} \cdot \frac{1}{2 (- \frac{1}{4})}$

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$d = \frac{7}{2} \cdot \frac{- 1 (- 1)}{2 (- \frac{1}{4})}$

Move the negative in front of the fraction.

$d = \frac{7}{2} (- \frac{1}{2 (\frac{1}{4})})$

Combine $2$ and $\frac{1}{4}$ .

$d = \frac{7}{2} (- \frac{1}{\frac{2}{4}})$

Cancel the common factor of $2$ and $4$ .

Factor $2$ out of $2$ .

$d = \frac{7}{2} (- \frac{1}{\frac{2 (1)}{4}})$

Cancel the common factors.

Factor $2$ out of $4$ .

$d = \frac{7}{2} (- \frac{1}{\frac{2 \cdot 1}{2 \cdot 2}})$

Cancel the common factor.

$d = \frac{7}{2} (- \frac{1}{\frac{2 \cdot 1}{2 \cdot 2}})$

Rewrite the expression.

$d = \frac{7}{2} (- \frac{1}{\frac{1}{2}})$

Multiply the numerator by the reciprocal of the denominator.

$d = \frac{7}{2} (- (1 \cdot 2))$

Cancel the common factor of $2$ .

Factor $2$ out of $- (1 \cdot 2)$ .

$d = \frac{7}{2} (2 (- 1 \cdot (1)))$

Cancel the common factor.

$d = \frac{7}{2} (2 (- 1 \cdot (1)))$

Rewrite the expression.

$d = 7 (- 1 \cdot (1))$

Multiply $- 1$ by $1$ .

$d = 7 \cdot - 1$

Multiply $7$ by $- 1$ .

$d = - 7$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - \frac{53}{4} - \frac{{(\frac{7}{2})}^{2}}{4 (- \frac{1}{4})}$

Simplify the right side.

Simplify each term.

Simplify the numerator.

Apply the product rule to $\frac{7}{2}$ .

$e = - \frac{53}{4} - \frac{\frac{7^{2}}{2^{2}}}{4 (- \frac{1}{4})}$

Raise $7$ to the power of $2$ .

$e = - \frac{53}{4} - \frac{\frac{49}{2^{2}}}{4 (- \frac{1}{4})}$

Raise $2$ to the power of $2$ .

$e = - \frac{53}{4} - \frac{\frac{49}{4}}{4 (- \frac{1}{4})}$

Simplify the denominator.

Multiply $- 1$ by $4$ .

$e = - \frac{53}{4} - \frac{\frac{49}{4}}{- 4 (\frac{1}{4})}$

Combine $- 4$ and $\frac{1}{4}$ .

$e = - \frac{53}{4} - \frac{\frac{49}{4}}{\frac{- 4}{4}}$

Divide $- 4$ by $4$ .

$e = - \frac{53}{4} - \frac{\frac{49}{4}}{- 1}$

Move the negative one from the denominator of $\frac{\frac{49}{4}}{- 1}$ .

$e = - \frac{53}{4} - (- 1 \cdot \frac{49}{4})$

Rewrite $- 1 \cdot \frac{49}{4}$ as $- \frac{49}{4}$ .

$e = - \frac{53}{4} - - \frac{49}{4}$

Multiply $- - \frac{49}{4}$ .

Multiply $- 1$ by $- 1$ .

$e = - \frac{53}{4} + 1 (\frac{49}{4})$

Multiply $\frac{49}{4}$ by $1$ .

$e = - \frac{53}{4} + \frac{49}{4}$

Combine the numerators over the common denominator.

$e = \frac{- 53 + 49}{4}$

Add $- 53$ and $49$ .

$e = \frac{- 4}{4}$

Divide $- 4$ by $4$ .

$e = - 1$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- \frac{1}{4} {(y - 7)}^{2} - 1$ .

$- \frac{1}{4} {(y - 7)}^{2} - 1$

Step 3

Set $x$ equal to the new right side.

$x = - \frac{1}{4} \cdot {(y - 7)}^{2} - 1$

Find the Vertex Form y^2+4x-14y=-53

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