Find the Vertex x^2-12x+7

$x^{2} - 12 x + 7$

Step 1

Rewrite the equation in vertex form.

Complete the square for $x^{2} - 12 x + 7$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - 12$

$c = 7$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 12}{2 \cdot 1}$

Cancel the common factor of $- 12$ and $2$ .

Factor $2$ out of $- 12$ .

$d = \frac{2 \cdot - 6}{2 \cdot 1}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot - 6}{2 (1)}$

Cancel the common factor.

$d = \frac{2 \cdot - 6}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{- 6}{1}$

Divide $- 6$ by $1$ .

$d = - 6$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 7 - \frac{{(- 12)}^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $- 12$ to the power of $2$ .

$e = 7 - \frac{144}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 7 - \frac{144}{4}$

Divide $144$ by $4$ .

$e = 7 - 1 \cdot 36$

Multiply $- 1$ by $36$ .

$e = 7 - 36$

Subtract $36$ from $7$ .

$e = - 29$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x - 6)}^{2} - 29$ .

${(x - 6)}^{2} - 29$

Set $y$ equal to the new right side.

$y = {(x - 6)}^{2} - 29$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = 6$

$k = - 29$

Step 3

Find the vertex $(h, k)$ .

$(6, - 29)$

Step 4

Find the Vertex x^2-12x+7

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