Find the Vertex y=5/4x^2

$y = \frac{5}{4} x^{2}$

Rewrite the equation in vertex form.

Combine $\frac{5}{4}$ and $x^{2}$ .

$y = \frac{5 x^{2}}{4}$

Complete the square for $\frac{5 x^{2}}{4}$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = \frac{5}{4}$

$b = 0$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 (\frac{5}{4})}$

Simplify the right side.

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 (\frac{5}{4})}$

Cancel the common factors.

Cancel the common factor.

$d = \frac{2 \cdot 0}{2 (\frac{5}{4})}$

Rewrite the expression.

$d = \frac{0}{\frac{5}{4}}$

Multiply the numerator by the reciprocal of the denominator.

$d = 0 (\frac{4}{5})$

Multiply $0$ by $\frac{4}{5}$ .

$d = 0$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{0^{2}}{4 (\frac{5}{4})}$

Simplify the right side.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$e = 0 - \frac{0}{4 (\frac{5}{4})}$

Combine $4$ and $\frac{5}{4}$ .

$e = 0 - \frac{0}{\frac{4 \cdot 5}{4}}$

Multiply $4$ by $5$ .

$e = 0 - \frac{0}{\frac{20}{4}}$

Divide $20$ by $4$ .

$e = 0 - \frac{0}{5}$

Divide $0$ by $5$ .

$e = 0 - 0$

Multiply $- 1$ by $0$ .

$e = 0 + 0$

Add $0$ and $0$ .

$e = 0$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $\frac{5}{4} x^{2}$ .

$\frac{5}{4} x^{2}$

Set $y$ equal to the new right side.

$y = \frac{5}{4} x^{2}$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = \frac{5}{4}$

$h = 0$

$k = 0$

Find the vertex $(h, k)$ .

$(0, 0)$

Find the Vertex y=5/4x^2

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