Find the x and y Intercepts 12x+15=-12y+15

$12 x + 15 = - 12 y + 15$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$12 x + 15 = - 12 \cdot 0 + 15$

Solve the equation.

Simplify $- 12 \cdot 0 + 15$ .

Multiply $- 12$ by $0$ .

$12 x + 15 = 0 + 15$

Add $0$ and $15$ .

$12 x + 15 = 15$

Move all terms not containing $x$ to the right side of the equation.

Subtract $15$ from both sides of the equation.

$12 x = 15 - 15$

Subtract $15$ from $15$ .

$12 x = 0$

Divide each term in $12 x = 0$ by $12$ and simplify.

Divide each term in $12 x = 0$ by $12$ .

$\frac{12 x}{12} = \frac{0}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 x}{12} = \frac{0}{12}$

Divide $x$ by $1$ .

$x = \frac{0}{12}$

Simplify the right side.

Divide $0$ by $12$ .

$x = 0$

x-intercept(s) in point form.

x-intercept(s): $(0, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$12 (0) + 15 = - 12 y + 15$

Solve the equation.

Rewrite the equation as $- 12 y + 15 = 12 (0) + 15$ .

$- 12 y + 15 = 12 (0) + 15$

Simplify $12 (0) + 15$ .

Multiply $12$ by $0$ .

$- 12 y + 15 = 0 + 15$

Add $0$ and $15$ .

$- 12 y + 15 = 15$

Move all terms not containing $y$ to the right side of the equation.

Subtract $15$ from both sides of the equation.

$- 12 y = 15 - 15$

Subtract $15$ from $15$ .

$- 12 y = 0$

Divide each term in $- 12 y = 0$ by $- 12$ and simplify.

Divide each term in $- 12 y = 0$ by $- 12$ .

$\frac{- 12 y}{- 12} = \frac{0}{- 12}$

Simplify the left side.

Cancel the common factor of $- 12$ .

Cancel the common factor.

$\frac{- 12 y}{- 12} = \frac{0}{- 12}$

Divide $y$ by $1$ .

$y = \frac{0}{- 12}$

Simplify the right side.

Divide $0$ by $- 12$ .

$y = 0$

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

Step 3

List the intersections.

x-intercept(s): $(0, 0)$

y-intercept(s): $(0, 0)$

Step 4

Find the x and y Intercepts 12x+15=-12y+15

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