Find the x and y Intercepts (-2x^2-4x)/(4x+8)

$\frac{- 2 x^{2} - 4 x}{4 x + 8}$

Write $\frac{- 2 x^{2} - 4 x}{4 x + 8}$ as an equation.

$y = \frac{- 2 x^{2} - 4 x}{4 x + 8}$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{- 2 x^{2} - 4 x}{4 x + 8}$

Solve the equation.

Set the numerator equal to zero.

$- 2 x^{2} - 4 x = 0$

Solve the equation for $x$ .

Factor $- 2 x$ out of $- 2 x^{2} - 4 x$ .

Factor $- 2 x$ out of $- 2 x^{2}$ .

$- 2 x \cdot x - 4 x = 0$

Factor $- 2 x$ out of $- 4 x$ .

$- 2 x \cdot x - 2 x \cdot 2 = 0$

Factor $- 2 x$ out of $- 2 x (x) - 2 x (2)$ .

$- 2 x (x + 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 2 = 0$

Set $x$ equal to $0$ .

$x = 0$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

The final solution is all the values that make $- 2 x (x + 2) = 0$ true.

$x = 0, - 2$

Exclude the solutions that do not make $0 = \frac{- 2 x^{2} - 4 x}{4 x + 8}$ true.

$x = 0$

x-intercept(s) in point form.

x-intercept(s): $(0, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{- 2 {(0)}^{2} - 4 \cdot 0}{4 (0) + 8}$

Solve the equation.

Remove parentheses.

$y = \frac{- 2 \cdot 0^{2} - 4 \cdot 0}{4 (0) + 8}$

Remove parentheses.

$y = \frac{- 2 {(0)}^{2} - 4 \cdot 0}{4 (0) + 8}$

Simplify $\frac{- 2 {(0)}^{2} - 4 \cdot 0}{4 (0) + 8}$ .

Simplify the numerator.

Raising $0$ to any positive power yields $0$ .

$y = \frac{- 2 \cdot 0 - 4 \cdot 0}{4 (0) + 8}$

Multiply $- 2$ by $0$ .

$y = \frac{0 - 4 \cdot 0}{4 (0) + 8}$

Multiply $- 4$ by $0$ .

$y = \frac{0 + 0}{4 (0) + 8}$

Add $0$ and $0$ .

$y = \frac{0}{4 (0) + 8}$

Simplify the denominator.

Multiply $4$ by $0$ .

$y = \frac{0}{0 + 8}$

Add $0$ and $8$ .

$y = \frac{0}{8}$

Divide $0$ by $8$ .

$y = 0$

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

List the intersections.

x-intercept(s): $(0, 0)$

y-intercept(s): $(0, 0)$

Find the x and y Intercepts (-2x^2-4x)/(4x+8)

Related Questions

Support LCMGCF.com by disabling your adblocker.