Find the x and y Intercepts 2x^2+8x-1

$2 x^{2} + 8 x - 1$

Step 1

Write $2 x^{2} + 8 x - 1$ as an equation.

$y = 2 x^{2} + 8 x - 1$

Step 2

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = 2 x^{2} + 8 x - 1$

Solve the equation.

Rewrite the equation as $2 x^{2} + 8 x - 1 = 0$ .

$2 x^{2} + 8 x - 1 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 2$ , $b = 8$ , and $c = - 1$ into the quadratic formula and solve for $x$ .

$\frac{- 8 \pm \sqrt{8^{2} - 4 \cdot (2 \cdot - 1)}}{2 \cdot 2}$

Simplify.

Simplify the numerator.

Raise $8$ to the power of $2$ .

$x = \frac{- 8 \pm \sqrt{64 - 4 \cdot 2 \cdot - 1}}{2 \cdot 2}$

Multiply $- 4 \cdot 2 \cdot - 1$ .

Multiply $- 4$ by $2$ .

$x = \frac{- 8 \pm \sqrt{64 - 8 \cdot - 1}}{2 \cdot 2}$

Multiply $- 8$ by $- 1$ .

$x = \frac{- 8 \pm \sqrt{64 + 8}}{2 \cdot 2}$

Add $64$ and $8$ .

$x = \frac{- 8 \pm \sqrt{72}}{2 \cdot 2}$

Rewrite $72$ as $6^{2} \cdot 2$ .

Factor $36$ out of $72$ .

$x = \frac{- 8 \pm \sqrt{36 (2)}}{2 \cdot 2}$

Rewrite $36$ as $6^{2}$ .

$x = \frac{- 8 \pm \sqrt{6^{2} \cdot 2}}{2 \cdot 2}$

Pull terms out from under the radical.

$x = \frac{- 8 \pm 6 \sqrt{2}}{2 \cdot 2}$

Multiply $2$ by $2$ .

$x = \frac{- 8 \pm 6 \sqrt{2}}{4}$

Simplify $\frac{- 8 \pm 6 \sqrt{2}}{4}$ .

$x = \frac{- 4 \pm 3 \sqrt{2}}{2}$

Simplify the expression to solve for the $+$ portion of the $\pm$ .

Simplify the numerator.

Raise $8$ to the power of $2$ .

$x = \frac{- 8 \pm \sqrt{64 - 4 \cdot 2 \cdot - 1}}{2 \cdot 2}$

Multiply $- 4 \cdot 2 \cdot - 1$ .

Multiply $- 4$ by $2$ .

$x = \frac{- 8 \pm \sqrt{64 - 8 \cdot - 1}}{2 \cdot 2}$

Multiply $- 8$ by $- 1$ .

$x = \frac{- 8 \pm \sqrt{64 + 8}}{2 \cdot 2}$

Add $64$ and $8$ .

$x = \frac{- 8 \pm \sqrt{72}}{2 \cdot 2}$

Rewrite $72$ as $6^{2} \cdot 2$ .

Factor $36$ out of $72$ .

$x = \frac{- 8 \pm \sqrt{36 (2)}}{2 \cdot 2}$

Rewrite $36$ as $6^{2}$ .

$x = \frac{- 8 \pm \sqrt{6^{2} \cdot 2}}{2 \cdot 2}$

Pull terms out from under the radical.

$x = \frac{- 8 \pm 6 \sqrt{2}}{2 \cdot 2}$

Multiply $2$ by $2$ .

$x = \frac{- 8 \pm 6 \sqrt{2}}{4}$

Simplify $\frac{- 8 \pm 6 \sqrt{2}}{4}$ .

$x = \frac{- 4 \pm 3 \sqrt{2}}{2}$

Change the $\pm$ to $+$ .

$x = \frac{- 4 + 3 \sqrt{2}}{2}$

Rewrite $- 4$ as $- 1 (4)$ .

$x = \frac{- 1 \cdot 4 + 3 \sqrt{2}}{2}$

Factor $- 1$ out of $3 \sqrt{2}$ .

$x = \frac{- 1 \cdot 4 - (- 3 \sqrt{2})}{2}$

Factor $- 1$ out of $- 1 (4) - (- 3 \sqrt{2})$ .

$x = \frac{- 1 (4 - 3 \sqrt{2})}{2}$

Move the negative in front of the fraction.

$x = - \frac{4 - 3 \sqrt{2}}{2}$

Simplify the expression to solve for the $-$ portion of the $\pm$ .

Simplify the numerator.

Raise $8$ to the power of $2$ .

$x = \frac{- 8 \pm \sqrt{64 - 4 \cdot 2 \cdot - 1}}{2 \cdot 2}$

Multiply $- 4 \cdot 2 \cdot - 1$ .

Multiply $- 4$ by $2$ .

$x = \frac{- 8 \pm \sqrt{64 - 8 \cdot - 1}}{2 \cdot 2}$

Multiply $- 8$ by $- 1$ .

$x = \frac{- 8 \pm \sqrt{64 + 8}}{2 \cdot 2}$

Add $64$ and $8$ .

$x = \frac{- 8 \pm \sqrt{72}}{2 \cdot 2}$

Rewrite $72$ as $6^{2} \cdot 2$ .

Factor $36$ out of $72$ .

$x = \frac{- 8 \pm \sqrt{36 (2)}}{2 \cdot 2}$

Rewrite $36$ as $6^{2}$ .

$x = \frac{- 8 \pm \sqrt{6^{2} \cdot 2}}{2 \cdot 2}$

Pull terms out from under the radical.

$x = \frac{- 8 \pm 6 \sqrt{2}}{2 \cdot 2}$

Multiply $2$ by $2$ .

$x = \frac{- 8 \pm 6 \sqrt{2}}{4}$

Simplify $\frac{- 8 \pm 6 \sqrt{2}}{4}$ .

$x = \frac{- 4 \pm 3 \sqrt{2}}{2}$

Change the $\pm$ to $-$ .

$x = \frac{- 4 - 3 \sqrt{2}}{2}$

Rewrite $- 4$ as $- 1 (4)$ .

$x = \frac{- 1 \cdot 4 - 3 \sqrt{2}}{2}$

Factor $- 1$ out of $- 3 \sqrt{2}$ .

$x = \frac{- 1 \cdot 4 - (3 \sqrt{2})}{2}$

Factor $- 1$ out of $- 1 (4) - (3 \sqrt{2})$ .

$x = \frac{- 1 (4 + 3 \sqrt{2})}{2}$

Move the negative in front of the fraction.

$x = - \frac{4 + 3 \sqrt{2}}{2}$

The final answer is the combination of both solutions.

$x = - \frac{4 - 3 \sqrt{2}}{2}, - \frac{4 + 3 \sqrt{2}}{2}$

x-intercept(s) in point form.

x-intercept(s): $(- \frac{4 - 3 \sqrt{2}}{2}, 0), (- \frac{4 + 3 \sqrt{2}}{2}, 0)$

Step 3

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = 2 {(0)}^{2} + 8 (0) - 1$

Solve the equation.

Remove parentheses.

$y = 2 \cdot 0^{2} + 8 (0) - 1$

Remove parentheses.

$y = 2 {(0)}^{2} + 8 (0) - 1$

Simplify $2 {(0)}^{2} + 8 (0) - 1$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$y = 2 \cdot 0 + 8 (0) - 1$

Multiply $2$ by $0$ .

$y = 0 + 8 (0) - 1$

Multiply $8$ by $0$ .

$y = 0 + 0 - 1$

Simplify by adding and subtracting.

Add $0$ and $0$ .

$y = 0 - 1$

Subtract $1$ from $0$ .

$y = - 1$

y-intercept(s) in point form.

y-intercept(s): $(0, - 1)$

Step 4

List the intersections.

x-intercept(s): $(- \frac{4 - 3 \sqrt{2}}{2}, 0), (- \frac{4 + 3 \sqrt{2}}{2}, 0)$

y-intercept(s): $(0, - 1)$

Step 5

Find the x and y Intercepts 2x^2+8x-1

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