Find the x and y Intercepts -2x^2+9x+18

$- 2 x^{2} + 9 x + 18$

Step 1

Write $- 2 x^{2} + 9 x + 18$ as an equation.

$y = - 2 x^{2} + 9 x + 18$

Step 2

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - 2 x^{2} + 9 x + 18$

Solve the equation.

Rewrite the equation as $- 2 x^{2} + 9 x + 18 = 0$ .

$- 2 x^{2} + 9 x + 18 = 0$

Factor the left side of the equation.

Factor $- 1$ out of $- 2 x^{2} + 9 x + 18$ .

Factor $- 1$ out of $- 2 x^{2}$ .

$- (2 x^{2}) + 9 x + 18 = 0$

Factor $- 1$ out of $9 x$ .

$- (2 x^{2}) - (- 9 x) + 18 = 0$

Rewrite $18$ as $- 1 (- 18)$ .

$- (2 x^{2}) - (- 9 x) - 1 \cdot - 18 = 0$

Factor $- 1$ out of $- (2 x^{2}) - (- 9 x)$ .

$- (2 x^{2} - 9 x) - 1 \cdot - 18 = 0$

Factor $- 1$ out of $- (2 x^{2} - 9 x) - 1 (- 18)$ .

$- (2 x^{2} - 9 x - 18) = 0$

Factor.

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot - 18 = - 36$ and whose sum is $b = - 9$ .

Factor $- 9$ out of $- 9 x$ .

$- (2 x^{2} - 9 x - 18) = 0$

Rewrite $- 9$ as $3$ plus $- 12$

$- (2 x^{2} + (3 - 12) x - 18) = 0$

Apply the distributive property.

$- (2 x^{2} + 3 x - 12 x - 18) = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$- ((2 x^{2} + 3 x) - 12 x - 18) = 0$

Factor out the greatest common factor (GCF) from each group.

$- (x (2 x + 3) - 6 (2 x + 3)) = 0$

Factor the polynomial by factoring out the greatest common factor, $2 x + 3$ .

$- ((2 x + 3) (x - 6)) = 0$

Remove unnecessary parentheses.

$- (2 x + 3) (x - 6) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$2 x + 3 = 0$

$x - 6 = 0$

Set $2 x + 3$ equal to $0$ and solve for $x$ .

Set $2 x + 3$ equal to $0$ .

$2 x + 3 = 0$

Solve $2 x + 3 = 0$ for $x$ .

Subtract $3$ from both sides of the equation.

$2 x = - 3$

Divide each term in $2 x = - 3$ by $2$ and simplify.

Divide each term in $2 x = - 3$ by $2$ .

$\frac{2 x}{2} = \frac{- 3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 3}{2}$

Divide $x$ by $1$ .

$x = \frac{- 3}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{3}{2}$

Set $x - 6$ equal to $0$ and solve for $x$ .

Set $x - 6$ equal to $0$ .

$x - 6 = 0$

Add $6$ to both sides of the equation.

$x = 6$

The final solution is all the values that make $- (2 x + 3) (x - 6) = 0$ true.

$x = - \frac{3}{2}, 6$

x-intercept(s) in point form.

x-intercept(s): $(- \frac{3}{2}, 0), (6, 0)$

Step 3

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - 2 {(0)}^{2} + 9 (0) + 18$

Solve the equation.

Remove parentheses.

$y = - 2 \cdot 0^{2} + 9 (0) + 18$

Remove parentheses.

$y = - 2 {(0)}^{2} + 9 (0) + 18$

Simplify $- 2 {(0)}^{2} + 9 (0) + 18$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$y = - 2 \cdot 0 + 9 (0) + 18$

Multiply $- 2$ by $0$ .

$y = 0 + 9 (0) + 18$

Multiply $9$ by $0$ .

$y = 0 + 0 + 18$

Simplify by adding numbers.

Add $0$ and $0$ .

$y = 0 + 18$

Add $0$ and $18$ .

$y = 18$

y-intercept(s) in point form.

y-intercept(s): $(0, 18)$

Step 4

List the intersections.

x-intercept(s): $(- \frac{3}{2}, 0), (6, 0)$

y-intercept(s): $(0, 18)$

Step 5

Find the x and y Intercepts -2x^2+9x+18

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