Find the x and y Intercepts 2x^2+y=8x-6

$2 x^{2} + y = 8 x - 6$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$2 x^{2} + 0 = 8 x - 6$

Solve the equation.

Add $2 x^{2}$ and $0$ .

$2 x^{2} = 8 x - 6$

Subtract $8 x$ from both sides of the equation.

$2 x^{2} - 8 x = - 6$

Add $6$ to both sides of the equation.

$2 x^{2} - 8 x + 6 = 0$

Factor the left side of the equation.

Factor $2$ out of $2 x^{2} - 8 x + 6$ .

Factor $2$ out of $2 x^{2}$ .

$2 (x^{2}) - 8 x + 6 = 0$

Factor $2$ out of $- 8 x$ .

$2 (x^{2}) + 2 (- 4 x) + 6 = 0$

Factor $2$ out of $6$ .

$2 x^{2} + 2 (- 4 x) + 2 \cdot 3 = 0$

Factor $2$ out of $2 x^{2} + 2 (- 4 x)$ .

$2 (x^{2} - 4 x) + 2 \cdot 3 = 0$

Factor $2$ out of $2 (x^{2} - 4 x) + 2 \cdot 3$ .

$2 (x^{2} - 4 x + 3) = 0$

Factor.

Factor $x^{2} - 4 x + 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $3$ and whose sum is $- 4$ .

$- 3, - 1$

Write the factored form using these integers.

$2 ((x - 3) (x - 1)) = 0$

Remove unnecessary parentheses.

$2 (x - 3) (x - 1) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 3 = 0$

$x - 1 = 0$

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Set $x - 1$ equal to $0$ and solve for $x$ .

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Add $1$ to both sides of the equation.

$x = 1$

The final solution is all the values that make $2 (x - 3) (x - 1) = 0$ true.

$x = 3, 1$

x-intercept(s) in point form.

x-intercept(s): $(3, 0), (1, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$2 {(0)}^{2} + y = 8 (0) - 6$

Solve the equation.

Simplify $2 {(0)}^{2} + y$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$2 \cdot 0 + y = 8 (0) - 6$

Multiply $2$ by $0$ .

$0 + y = 8 (0) - 6$

Add $0$ and $y$ .

$y = 8 (0) - 6$

Simplify $8 (0) - 6$ .

Multiply $8$ by $0$ .

$y = 0 - 6$

Subtract $6$ from $0$ .

$y = - 6$

y-intercept(s) in point form.

y-intercept(s): $(0, - 6)$

List the intersections.

x-intercept(s): $(3, 0), (1, 0)$

y-intercept(s): $(0, - 6)$

Find the x and y Intercepts 2x^2+y=8x-6

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