Find the x and y Intercepts 2x+3y=-9

$2 x + 3 y = - 9$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$2 x + 3 (0) = - 9$

Solve the equation.

Simplify $2 x + 3 (0)$ .

Multiply $3$ by $0$ .

$2 x + 0 = - 9$

Add $2 x$ and $0$ .

$2 x = - 9$

Divide each term in $2 x = - 9$ by $2$ and simplify.

Divide each term in $2 x = - 9$ by $2$ .

$\frac{2 x}{2} = \frac{- 9}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 9}{2}$

Divide $x$ by $1$ .

$x = \frac{- 9}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{9}{2}$

x-intercept(s) in point form.

x-intercept(s): $(- \frac{9}{2}, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$2 (0) + 3 y = - 9$

Solve the equation.

Simplify $2 (0) + 3 y$ .

Multiply $2$ by $0$ .

$0 + 3 y = - 9$

Add $0$ and $3 y$ .

$3 y = - 9$

Divide each term in $3 y = - 9$ by $3$ and simplify.

Divide each term in $3 y = - 9$ by $3$ .

$\frac{3 y}{3} = \frac{- 9}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 9}{3}$

Divide $y$ by $1$ .

$y = \frac{- 9}{3}$

Simplify the right side.

Divide $- 9$ by $3$ .

$y = - 3$

y-intercept(s) in point form.

y-intercept(s): $(0, - 3)$

Step 3

List the intersections.

x-intercept(s): $(- \frac{9}{2}, 0)$

y-intercept(s): $(0, - 3)$

Step 4

Find the x and y Intercepts 2x+3y=-9

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