Find the x and y Intercepts -2x^4-6x^3

$- 2 x^{4} - 6 x^{3}$

Step 1

Write $- 2 x^{4} - 6 x^{3}$ as an equation.

$y = - 2 x^{4} - 6 x^{3}$

Step 2

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - 2 x^{4} - 6 x^{3}$

Solve the equation.

Rewrite the equation as $- 2 x^{4} - 6 x^{3} = 0$ .

$- 2 x^{4} - 6 x^{3} = 0$

Factor $- 2 x^{3}$ out of $- 2 x^{4} - 6 x^{3}$ .

Factor $- 2 x^{3}$ out of $- 2 x^{4}$ .

$- 2 x^{3} x - 6 x^{3} = 0$

Factor $- 2 x^{3}$ out of $- 6 x^{3}$ .

$- 2 x^{3} x - 2 x^{3} \cdot 3 = 0$

Factor $- 2 x^{3}$ out of $- 2 x^{3} (x) - 2 x^{3} (3)$ .

$- 2 x^{3} (x + 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{3} = 0$

$x + 3 = 0$

Set $x^{3}$ equal to $0$ and solve for $x$ .

Set $x^{3}$ equal to $0$ .

$x^{3} = 0$

Solve $x^{3} = 0$ for $x$ .

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[3]{0}$

Simplify $\sqrt[3]{0}$ .

Rewrite $0$ as $0^{3}$ .

$x = \sqrt[3]{0^{3}}$

Pull terms out from under the radical, assuming real numbers.

$x = 0$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

The final solution is all the values that make $- 2 x^{3} (x + 3) = 0$ true.

$x = 0, - 3$

x-intercept(s) in point form.

x-intercept(s): $(0, 0), (- 3, 0)$

Step 3

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - 2 {(0)}^{4} - 6 {(0)}^{3}$

Solve the equation.

Remove parentheses.

$y = - 2 \cdot 0^{4} - 6 {(0)}^{3}$

Remove parentheses.

$y = - 2 \cdot 0^{4} - 6 \cdot 0^{3}$

Remove parentheses.

$y = - 2 {(0)}^{4} - 6 {(0)}^{3}$

Simplify $- 2 {(0)}^{4} - 6 {(0)}^{3}$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$y = - 2 \cdot 0 - 6 {(0)}^{3}$

Multiply $- 2$ by $0$ .

$y = 0 - 6 {(0)}^{3}$

Raising $0$ to any positive power yields $0$ .

$y = 0 - 6 \cdot 0$

Multiply $- 6$ by $0$ .

$y = 0 + 0$

Add $0$ and $0$ .

$y = 0$

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

Step 4

List the intersections.

x-intercept(s): $(0, 0), (- 3, 0)$

y-intercept(s): $(0, 0)$

Step 5

Find the x and y Intercepts -2x^4-6x^3

Related Questions

Support LCMGCF.com by disabling your adblocker.