Find the x and y Intercepts (-2x+8)/(x^2-4x)

$\frac{- 2 x + 8}{x^{2} - 4 x}$

Write $\frac{- 2 x + 8}{x^{2} - 4 x}$ as an equation.

$y = \frac{- 2 x + 8}{x^{2} - 4 x}$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{- 2 x + 8}{x^{2} - 4 x}$

Solve the equation.

Set the numerator equal to zero.

$- 2 x + 8 = 0$

Solve the equation for $x$ .

Subtract $8$ from both sides of the equation.

$- 2 x = - 8$

Divide each term in $- 2 x = - 8$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 8$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 8}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 8}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 8}{- 2}$

Simplify the right side.

Divide $- 8$ by $- 2$ .

$x = 4$

Exclude the solutions that do not make $0 = \frac{- 2 x + 8}{x^{2} - 4 x}$ true.

$No solution$

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

x-intercept(s): $None$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{- 2 \cdot 0 + 8}{{(0)}^{2} - 4 \cdot 0}$

The equation has an undefined fraction.

Undefined

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

y-intercept(s): $None$

List the intersections.

x-intercept(s): $None$

y-intercept(s): $None$