Find the x and y Intercepts 3x+12=-6

$3 x + 12 = - 6$

Find the x-intercepts.

Solve the equation for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$3 x = - 6 - 12$

Subtract $12$ from $- 6$ .

$3 x = - 18$

Divide each term in $3 x = - 18$ by $3$ and simplify.

Divide each term in $3 x = - 18$ by $3$ .

$\frac{3 x}{3} = \frac{- 18}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 18}{3}$

Divide $x$ by $1$ .

$x = \frac{- 18}{3}$

Simplify the right side.

Divide $- 18$ by $3$ .

$x = - 6$

Since $x = - 6$ is a vertical line, the x-intercept(s) is equal to the value of $x$ .

x-intercept(s): $- 6$

Since $x = - 6$ is a vertical line, the y-intercept(s) is equal to the value of $x$ .

y-intercept(s): $None$

List the intersections.

x-intercept(s): $- 6$

y-intercept(s): $None$