Find the x and y Intercepts (3x^2+12x)/(-2x^2+2x)

$\frac{3 x^{2} + 12 x}{- 2 x^{2} + 2 x}$

Write $\frac{3 x^{2} + 12 x}{- 2 x^{2} + 2 x}$ as an equation.

$y = \frac{3 x^{2} + 12 x}{- 2 x^{2} + 2 x}$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{3 x^{2} + 12 x}{- 2 x^{2} + 2 x}$

Solve the equation.

Set the numerator equal to zero.

$3 x^{2} + 12 x = 0$

Solve the equation for $x$ .

Factor $3 x$ out of $3 x^{2} + 12 x$ .

Factor $3 x$ out of $3 x^{2}$ .

$3 x (x) + 12 x = 0$

Factor $3 x$ out of $12 x$ .

$3 x (x) + 3 x (4) = 0$

Factor $3 x$ out of $3 x (x) + 3 x (4)$ .

$3 x (x + 4) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 4 = 0$

Set $x$ equal to $0$ .

$x = 0$

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

The final solution is all the values that make $3 x (x + 4) = 0$ true.

$x = 0, - 4$

Exclude the solutions that do not make $0 = \frac{3 x^{2} + 12 x}{- 2 x^{2} + 2 x}$ true.

$x = - 4$

x-intercept(s) in point form.

x-intercept(s): $(- 4, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{3 {(0)}^{2} + 12 (0)}{- 2 {(0)}^{2} + 2 (0)}$

The equation has an undefined fraction.

Undefined

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

y-intercept(s): $None$

List the intersections.

x-intercept(s): $(- 4, 0)$

y-intercept(s): $None$