Find the x and y Intercepts 3x-4y=12

$3 x - 4 y = 12$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$3 x - 4 \cdot 0 = 12$

Solve the equation.

Simplify $3 x - 4 \cdot 0$ .

Multiply $- 4$ by $0$ .

$3 x + 0 = 12$

Add $3 x$ and $0$ .

$3 x = 12$

Divide each term in $3 x = 12$ by $3$ and simplify.

Divide each term in $3 x = 12$ by $3$ .

$\frac{3 x}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{12}{3}$

Divide $x$ by $1$ .

$x = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$x = 4$

x-intercept(s) in point form.

x-intercept(s): $(4, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$3 (0) - 4 y = 12$

Solve the equation.

Simplify $3 (0) - 4 y$ .

Multiply $3$ by $0$ .

$0 - 4 y = 12$

Subtract $4 y$ from $0$ .

$- 4 y = 12$

Divide each term in $- 4 y = 12$ by $- 4$ and simplify.

Divide each term in $- 4 y = 12$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{12}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{12}{- 4}$

Divide $y$ by $1$ .

$y = \frac{12}{- 4}$

Simplify the right side.

Divide $12$ by $- 4$ .

$y = - 3$

y-intercept(s) in point form.

y-intercept(s): $(0, - 3)$

List the intersections.

x-intercept(s): $(4, 0)$

y-intercept(s): $(0, - 3)$

Find the x and y Intercepts 3x-4y=12

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