Find the x and y Intercepts -3x+9y=18

$- 3 x + 9 y = 18$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$- 3 x + 9 (0) = 18$

Solve the equation.

Simplify $- 3 x + 9 (0)$ .

Multiply $9$ by $0$ .

$- 3 x + 0 = 18$

Add $- 3 x$ and $0$ .

$- 3 x = 18$

Divide each term in $- 3 x = 18$ by $- 3$ and simplify.

Divide each term in $- 3 x = 18$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{18}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{18}{- 3}$

Divide $x$ by $1$ .

$x = \frac{18}{- 3}$

Simplify the right side.

Divide $18$ by $- 3$ .

$x = - 6$

x-intercept(s) in point form.

x-intercept(s): $(- 6, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$- 3 \cdot 0 + 9 y = 18$

Solve the equation.

Simplify $- 3 \cdot 0 + 9 y$ .

Multiply $- 3$ by $0$ .

$0 + 9 y = 18$

Add $0$ and $9 y$ .

$9 y = 18$

Divide each term in $9 y = 18$ by $9$ and simplify.

Divide each term in $9 y = 18$ by $9$ .

$\frac{9 y}{9} = \frac{18}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 y}{9} = \frac{18}{9}$

Divide $y$ by $1$ .

$y = \frac{18}{9}$

Simplify the right side.

Divide $18$ by $9$ .

$y = 2$

y-intercept(s) in point form.

y-intercept(s): $(0, 2)$

List the intersections.

x-intercept(s): $(- 6, 0)$

y-intercept(s): $(0, 2)$

Find the x and y Intercepts -3x+9y=18

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