Find the x and y Intercepts -4/(x^2-3x)

$- \frac{4}{x^{2} - 3 x}$

Step 1

Write $- \frac{4}{x^{2} - 3 x}$ as an equation.

$y = - \frac{4}{x^{2} - 3 x}$

Step 2

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - \frac{4}{x^{2} - 3 x}$

Solve the equation.

Set the numerator equal to zero.

$4 = 0$

Since $4 \neq 0$ , there are no solutions.

No solution

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

x-intercept(s): $None$

Step 3

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - \frac{4}{{(0)}^{2} - 3 \cdot 0}$

The equation has an undefined fraction.

Undefined

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

y-intercept(s): $None$

Step 4

List the intersections.

x-intercept(s): $None$

y-intercept(s): $None$

Step 5