Find the x and y Intercepts f(x)=(10x^2)/(x^4+25)

$f (x) = \frac{10 x^{2}}{x^{4} + 25}$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{10 x^{2}}{x^{4} + 25}$

Solve the equation.

Set the numerator equal to zero.

$10 x^{2} = 0$

Solve the equation for $x$ .

Divide each term in $10 x^{2} = 0$ by $10$ and simplify.

Divide each term in $10 x^{2} = 0$ by $10$ .

$\frac{10 x^{2}}{10} = \frac{0}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 x^{2}}{10} = \frac{0}{10}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{0}{10}$

Simplify the right side.

Divide $0$ by $10$ .

$x^{2} = 0$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{0}$

Simplify $\pm \sqrt{0}$ .

Rewrite $0$ as $0^{2}$ .

$x = \pm \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 0$

Plus or minus $0$ is $0$ .

$x = 0$

x-intercept(s) in point form.

x-intercept(s): $(0, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{10 {(0)}^{2}}{{(0)}^{4} + 25}$

Solve the equation.

Remove parentheses.

$y = \frac{10 \cdot 0^{2}}{{(0)}^{4} + 25}$

Remove parentheses.

$y = \frac{10 \cdot 0^{2}}{0^{4} + 25}$

Remove parentheses.

$y = \frac{10 {(0)}^{2}}{{(0)}^{4} + 25}$

Simplify $\frac{10 {(0)}^{2}}{{(0)}^{4} + 25}$ .

Raising $0$ to any positive power yields $0$ .

$y = \frac{10 \cdot 0}{0^{4} + 25}$

Simplify the denominator.

Raising $0$ to any positive power yields $0$ .

$y = \frac{10 \cdot 0}{0 + 25}$

Add $0$ and $25$ .

$y = \frac{10 \cdot 0}{25}$

Simplify the expression.

Multiply $10$ by $0$ .

$y = \frac{0}{25}$

Divide $0$ by $25$ .

$y = 0$

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

Step 3

List the intersections.

x-intercept(s): $(0, 0)$

y-intercept(s): $(0, 0)$

Step 4

Find the x and y Intercepts f(x)=(10x^2)/(x^4+25)

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