Find the x and y Intercepts f(x)=-2((1^x)/3)

$f (x) = - 2 (\frac{1^{x}}{3})$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - 2 \frac{1^{x}}{3}$

Solve the equation.

Rewrite the equation as $- 2 \frac{1^{x}}{3} = 0$ .

$- 2 \frac{1^{x}}{3} = 0$

Simplify $- 2 \frac{1^{x}}{3}$ .

One to any power is one.

$- 2 (\frac{1}{3}) = 0$

Combine $- 2$ and $\frac{1}{3}$ .

$\frac{- 2}{3} = 0$

Move the negative in front of the fraction.

$- \frac{2}{3} = 0$

Set the numerator equal to zero.

$2 = 0$

Since $2 \neq 0$ , there are no solutions.

No solution

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

x-intercept(s): $None$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - 2 \frac{1^{0}}{3}$

Solve the equation.

Remove parentheses.

$y = - 2 \frac{1^{0}}{3}$

Simplify $- 2 \frac{1^{0}}{3}$ .

Anything raised to $0$ is $1$ .

$y = - 2 (\frac{1}{3})$

Combine $- 2$ and $\frac{1}{3}$ .

$y = \frac{- 2}{3}$

Move the negative in front of the fraction.

$y = - \frac{2}{3}$

y-intercept(s) in point form.

y-intercept(s): $(0, - \frac{2}{3})$

List the intersections.

x-intercept(s): $None$

y-intercept(s): $(0, - \frac{2}{3})$