Find the x and y Intercepts f(x)=2x^2+9x-5

$f (x) = 2 x^{2} + 9 x - 5$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = 2 x^{2} + 9 x - 5$

Solve the equation.

Rewrite the equation as $2 x^{2} + 9 x - 5 = 0$ .

$2 x^{2} + 9 x - 5 = 0$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot - 5 = - 10$ and whose sum is $b = 9$ .

Factor $9$ out of $9 x$ .

$2 x^{2} + 9 (x) - 5 = 0$

Rewrite $9$ as $- 1$ plus $10$

$2 x^{2} + (- 1 + 10) x - 5 = 0$

Apply the distributive property.

$2 x^{2} - 1 x + 10 x - 5 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(2 x^{2} - 1 x) + 10 x - 5 = 0$

Factor out the greatest common factor (GCF) from each group.

$x (2 x - 1) + 5 (2 x - 1) = 0$

Factor the polynomial by factoring out the greatest common factor, $2 x - 1$ .

$(2 x - 1) (x + 5) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$2 x - 1 = 0$

$x + 5 = 0$

Set $2 x - 1$ equal to $0$ and solve for $x$ .

Set $2 x - 1$ equal to $0$ .

$2 x - 1 = 0$

Solve $2 x - 1 = 0$ for $x$ .

Add $1$ to both sides of the equation.

$2 x = 1$

Divide each term in $2 x = 1$ by $2$ and simplify.

Divide each term in $2 x = 1$ by $2$ .

$\frac{2 x}{2} = \frac{1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{1}{2}$

Divide $x$ by $1$ .

$x = \frac{1}{2}$

Set $x + 5$ equal to $0$ and solve for $x$ .

Set $x + 5$ equal to $0$ .

$x + 5 = 0$

Subtract $5$ from both sides of the equation.

$x = - 5$

The final solution is all the values that make $(2 x - 1) (x + 5) = 0$ true.

$x = \frac{1}{2}, - 5$

x-intercept(s) in point form.

x-intercept(s): $(\frac{1}{2}, 0), (- 5, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = 2 {(0)}^{2} + 9 (0) - 5$

Solve the equation.

Remove parentheses.

$y = 2 \cdot 0^{2} + 9 (0) - 5$

Remove parentheses.

$y = 2 {(0)}^{2} + 9 (0) - 5$

Simplify $2 {(0)}^{2} + 9 (0) - 5$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$y = 2 \cdot 0 + 9 (0) - 5$

Multiply $2$ by $0$ .

$y = 0 + 9 (0) - 5$

Multiply $9$ by $0$ .

$y = 0 + 0 - 5$

Simplify by adding and subtracting.

Add $0$ and $0$ .

$y = 0 - 5$

Subtract $5$ from $0$ .

$y = - 5$

y-intercept(s) in point form.

y-intercept(s): $(0, - 5)$

Step 3

List the intersections.

x-intercept(s): $(\frac{1}{2}, 0), (- 5, 0)$

y-intercept(s): $(0, - 5)$

Step 4

Find the x and y Intercepts f(x)=2x^2+9x-5

Related Questions

Support LCMGCF.com by disabling your adblocker.