Find the x and y Intercepts f(x)=(-2x)/3+2

$f (x) = \frac{- 2 x}{3} + 2$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{- 2 x}{3} + 2$

Solve the equation.

Rewrite the equation as $\frac{- 2 x}{3} + 2 = 0$ .

$\frac{- 2 x}{3} + 2 = 0$

Move the negative in front of the fraction.

$- \frac{2 x}{3} + 2 = 0$

Subtract $2$ from both sides of the equation.

$- \frac{2 x}{3} = - 2$

Multiply both sides of the equation by $- \frac{3}{2}$ .

$- \frac{3}{2} (- \frac{2 x}{3}) = - \frac{3}{2} \cdot - 2$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{3}{2} (- \frac{2 x}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{3}{2}$ into the numerator.

$\frac{- 3}{2} (- \frac{2 x}{3}) = - \frac{3}{2} \cdot - 2$

Move the leading negative in $- \frac{2 x}{3}$ into the numerator.

$\frac{- 3}{2} \cdot \frac{- 2 x}{3} = - \frac{3}{2} \cdot - 2$

Factor $3$ out of $- 3$ .

$\frac{3 (- 1)}{2} \cdot \frac{- 2 x}{3} = - \frac{3}{2} \cdot - 2$

Cancel the common factor.

$\frac{3 \cdot - 1}{2} \cdot \frac{- 2 x}{3} = - \frac{3}{2} \cdot - 2$

Rewrite the expression.

$\frac{- 1}{2} (- 2 x) = - \frac{3}{2} \cdot - 2$

Cancel the common factor of $2$ .

Factor $2$ out of $- 2 x$ .

$\frac{- 1}{2} (2 (- x)) = - \frac{3}{2} \cdot - 2$

Cancel the common factor.

$\frac{- 1}{2} (2 (- x)) = - \frac{3}{2} \cdot - 2$

Rewrite the expression.

$- - x = - \frac{3}{2} \cdot - 2$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{3}{2} \cdot - 2$

Multiply $x$ by $1$ .

$x = - \frac{3}{2} \cdot - 2$

Simplify the right side.

Simplify $- \frac{3}{2} \cdot - 2$ .

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{3}{2}$ into the numerator.

$x = \frac{- 3}{2} \cdot - 2$

Factor $2$ out of $- 2$ .

$x = \frac{- 3}{2} \cdot (2 (- 1))$

Cancel the common factor.

$x = \frac{- 3}{2} \cdot (2 \cdot - 1)$

Rewrite the expression.

$x = - 3 \cdot - 1$

Multiply $- 3$ by $- 1$ .

$x = 3$

x-intercept(s) in point form.

x-intercept(s): $(3, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{- 2 \cdot 0}{3} + 2$

Solve the equation.

Remove parentheses.

$y = \frac{- 2 \cdot 0}{3} + 2$

Simplify $\frac{- 2 \cdot 0}{3} + 2$ .

Multiply $- 2$ by $0$ .

$y = \frac{0}{3} + 2$

Divide $0$ by $3$ .

$y = 0 + 2$

Add $0$ and $2$ .

$y = 2$

y-intercept(s) in point form.

y-intercept(s): $(0, 2)$

List the intersections.

x-intercept(s): $(3, 0)$

y-intercept(s): $(0, 2)$

Find the x and y Intercepts f(x)=(-2x)/3+2

Related Questions

Support LCMGCF.com by disabling your adblocker.