Find the x and y Intercepts f(x)=(x+1)-2

$f (x) = (x + 1) - 2$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = (x + 1) - 2$

Solve the equation.

Rewrite the equation as $x + 1 - 2 = 0$ .

$x + 1 - 2 = 0$

Subtract $2$ from $1$ .

$x - 1 = 0$

Add $1$ to both sides of the equation.

$x = 1$

x-intercept(s) in point form.

x-intercept(s): $(1, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = ((0) + 1) - 2$

Solve the equation.

Remove parentheses.

$y = 0 + 1 - 2$

Remove parentheses.

$y = ((0) + 1) - 2$

Simplify $((0) + 1) - 2$ .

Add $0$ and $1$ .

$y = 1 - 2$

Subtract $2$ from $1$ .

$y = - 1$

y-intercept(s) in point form.

y-intercept(s): $(0, - 1)$

List the intersections.

x-intercept(s): $(1, 0)$

y-intercept(s): $(0, - 1)$