Find the x and y Intercepts f(x)=-(x+1)(x-1)(x-3)

$f (x) = - (x + 1) (x - 1) (x - 3)$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - (x + 1) (x - 1) (x - 3)$

Solve the equation.

Rewrite the equation as $- (x + 1) (x - 1) (x - 3) = 0$ .

$- (x + 1) (x - 1) (x - 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$x - 1 = 0$

$x - 3 = 0$

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Set $x - 1$ equal to $0$ and solve for $x$ .

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Add $1$ to both sides of the equation.

$x = 1$

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

The final solution is all the values that make $- (x + 1) (x - 1) (x - 3) = 0$ true.

$x = - 1, 1, 3$

x-intercept(s) in point form.

x-intercept(s): $(- 1, 0), (1, 0), (3, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - ((0) + 1) ((0) - 1) ((0) - 3)$

Solve the equation.

Remove parentheses.

$y = - (0 + 1) ((0) - 1) ((0) - 3)$

Remove parentheses.

$y = - (0 + 1) (0 - 1) ((0) - 3)$

Remove parentheses.

$y = - (0 + 1) (0 - 1) (0 - 3)$

Remove parentheses.

$y = - ((0) + 1) ((0) - 1) ((0) - 3)$

Simplify $- ((0) + 1) ((0) - 1) ((0) - 3)$ .

Add $0$ and $1$ .

$y = - 1 \cdot 1 ((0) - 1) ((0) - 3)$

Multiply $- 1$ by $1$ .

$y = - 1 ((0) - 1) ((0) - 3)$

Subtract $1$ from $0$ .

$y = - 1 \cdot - 1 ((0) - 3)$

Multiply $- 1$ by $- 1$ .

$y = 1 ((0) - 3)$

Multiply $(0) - 3$ by $1$ .

$y = (0) - 3$

Subtract $3$ from $0$ .

$y = - 3$

y-intercept(s) in point form.

y-intercept(s): $(0, - 3)$

List the intersections.

x-intercept(s): $(- 1, 0), (1, 0), (3, 0)$

y-intercept(s): $(0, - 3)$

Find the x and y Intercepts f(x)=-(x+1)(x-1)(x-3)

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