Find the x and y Intercepts f(x)=(x-5)(5x+2)

$f (x) = (x - 5) (5 x + 2)$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = (x - 5) (5 x + 2)$

Solve the equation.

Rewrite the equation as $(x - 5) (5 x + 2) = 0$ .

$(x - 5) (5 x + 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 5 = 0$

$5 x + 2 = 0$

Set $x - 5$ equal to $0$ and solve for $x$ .

Set $x - 5$ equal to $0$ .

$x - 5 = 0$

Add $5$ to both sides of the equation.

$x = 5$

Set $5 x + 2$ equal to $0$ and solve for $x$ .

Set $5 x + 2$ equal to $0$ .

$5 x + 2 = 0$

Solve $5 x + 2 = 0$ for $x$ .

Subtract $2$ from both sides of the equation.

$5 x = - 2$

Divide each term in $5 x = - 2$ by $5$ and simplify.

Divide each term in $5 x = - 2$ by $5$ .

$\frac{5 x}{5} = \frac{- 2}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{- 2}{5}$

Divide $x$ by $1$ .

$x = \frac{- 2}{5}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{2}{5}$

The final solution is all the values that make $(x - 5) (5 x + 2) = 0$ true.

$x = 5, - \frac{2}{5}$

x-intercept(s) in point form.

x-intercept(s): $(5, 0), (- \frac{2}{5}, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = ((0) - 5) (5 (0) + 2)$

Solve the equation.

Remove parentheses.

$y = (0 - 5) (5 (0) + 2)$

Remove parentheses.

$y = ((0) - 5) (5 (0) + 2)$

Simplify $((0) - 5) (5 (0) + 2)$ .

Subtract $5$ from $0$ .

$y = - 5 (5 (0) + 2)$

Multiply $5$ by $0$ .

$y = - 5 (0 + 2)$

Add $0$ and $2$ .

$y = - 5 \cdot 2$

Multiply $- 5$ by $2$ .

$y = - 10$

y-intercept(s) in point form.

y-intercept(s): $(0, - 10)$

Step 3

List the intersections.

x-intercept(s): $(5, 0), (- \frac{2}{5}, 0)$

y-intercept(s): $(0, - 10)$

Step 4

Find the x and y Intercepts f(x)=(x-5)(5x+2)

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