Find the x and y Intercepts h(x)=-3(x-4)(x+2)

$h (x) = - 3 (x - 4) (x + 2)$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - 3 (x - 4) (x + 2)$

Solve the equation.

Rewrite the equation as $- 3 (x - 4) (x + 2) = 0$ .

$- 3 (x - 4) (x + 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 4 = 0$

$x + 2 = 0$

Set $x - 4$ equal to $0$ and solve for $x$ .

Set $x - 4$ equal to $0$ .

$x - 4 = 0$

Add $4$ to both sides of the equation.

$x = 4$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

The final solution is all the values that make $- 3 (x - 4) (x + 2) = 0$ true.

$x = 4, - 2$

x-intercept(s) in point form.

x-intercept(s): $(4, 0), (- 2, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - 3 ((0) - 4) ((0) + 2)$

Solve the equation.

Remove parentheses.

$y = - 3 (0 - 4) ((0) + 2)$

Remove parentheses.

$y = - 3 (0 - 4) (0 + 2)$

Remove parentheses.

$y = - 3 ((0) - 4) ((0) + 2)$

Simplify $- 3 ((0) - 4) ((0) + 2)$ .

Subtract $4$ from $0$ .

$y = - 3 \cdot - 4 ((0) + 2)$

Multiply $- 3$ by $- 4$ .

$y = 12 ((0) + 2)$

Add $0$ and $2$ .

$y = 12 \cdot 2$

Multiply $12$ by $2$ .

$y = 24$

y-intercept(s) in point form.

y-intercept(s): $(0, 24)$

Step 3

List the intersections.

x-intercept(s): $(4, 0), (- 2, 0)$

y-intercept(s): $(0, 24)$

Step 4

Find the x and y Intercepts h(x)=-3(x-4)(x+2)

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