Find the x and y Intercepts (x-1)(x+4)=y

$(x - 1) (x + 4) = y$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$(x - 1) (x + 4) = 0$

Solve the equation.

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 1 = 0$

$x + 4 = 0$

Set $x - 1$ equal to $0$ and solve for $x$ .

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Add $1$ to both sides of the equation.

$x = 1$

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

The final solution is all the values that make $(x - 1) (x + 4) = 0$ true.

$x = 1, - 4$

x-intercept(s) in point form.

x-intercept(s): $(1, 0), (- 4, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$((0) - 1) ((0) + 4) = y$

Solve the equation.

Rewrite the equation as $y = ((0) - 1) ((0) + 4)$ .

$y = ((0) - 1) ((0) + 4)$

Simplify $((0) - 1) ((0) + 4)$ .

Subtract $1$ from $0$ .

$y = - 1 ((0) + 4)$

Add $0$ and $4$ .

$y = - 1 \cdot 4$

Multiply $- 1$ by $4$ .

$y = - 4$

y-intercept(s) in point form.

y-intercept(s): $(0, - 4)$

List the intersections.

x-intercept(s): $(1, 0), (- 4, 0)$

y-intercept(s): $(0, - 4)$