Find the x and y Intercepts (x+2)(x+3)=y

$(x + 2) (x + 3) = y$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$(x + 2) (x + 3) = 0$

Solve the equation.

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 2 = 0$

$x + 3 = 0$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

The final solution is all the values that make $(x + 2) (x + 3) = 0$ true.

$x = - 2, - 3$

x-intercept(s) in point form.

x-intercept(s): $(- 2, 0), (- 3, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$((0) + 2) ((0) + 3) = y$

Solve the equation.

Rewrite the equation as $y = ((0) + 2) ((0) + 3)$ .

$y = ((0) + 2) ((0) + 3)$

Simplify $((0) + 2) ((0) + 3)$ .

Add $0$ and $2$ .

$y = 2 ((0) + 3)$

Add $0$ and $3$ .

$y = 2 \cdot 3$

Multiply $2$ by $3$ .

$y = 6$

y-intercept(s) in point form.

y-intercept(s): $(0, 6)$

List the intersections.

x-intercept(s): $(- 2, 0), (- 3, 0)$

y-intercept(s): $(0, 6)$