Find the x and y Intercepts (x^2+x-6)/(-4x^2-16x-12)

Consider the form ${\displaystyle x^2+bx+c}$. Find a pair of integers whose product is ${\displaystyle c}$ and whose sum is ${\displaystyle b}$. In this case, whose product is ${\displaystyle -6}$ and whose sum is ${\displaystyle 1}$.

Write the factored form using these integers.

Set ${\displaystyle x-2}$ equal to ${\displaystyle 0}$.

Add ${\displaystyle 2}$ to both sides of the equation.

Set ${\displaystyle x+3}$ equal to ${\displaystyle 0}$.

Subtract ${\displaystyle 3}$ from both sides of the equation.

Raising ${\displaystyle 0}$ to any positive power yields ${\displaystyle 0}$.

Add ${\displaystyle 0}$ and ${\displaystyle 0}$.

Subtract ${\displaystyle 6}$ from ${\displaystyle 0}$.

Raising ${\displaystyle 0}$ to any positive power yields ${\displaystyle 0}$.

Multiply ${\displaystyle -4}$ by ${\displaystyle 0}$.

Multiply ${\displaystyle -16}$ by ${\displaystyle 0}$.

Add ${\displaystyle 0}$ and ${\displaystyle 0}$.

Subtract ${\displaystyle 12}$ from ${\displaystyle 0}$.

Factor ${\displaystyle -6}$ out of ${\displaystyle -6}$.

Cancel the common factors.