Find the x and y Intercepts x^2+y-1=0

$x^{2} + y - 1 = 0$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$x^{2} + 0 - 1 = 0$

Solve the equation.

Add $x^{2}$ and $0$ .

$x^{2} - 1 = 0$

Add $1$ to both sides of the equation.

$x^{2} = 1$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{1}$

Any root of $1$ is $1$ .

$x = \pm 1$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 1$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 1, - 1$

x-intercept(s) in point form.

x-intercept(s): $(1, 0), (- 1, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

${(0)}^{2} + y - 1 = 0$

Solve the equation.

Simplify ${(0)}^{2} + y - 1$ .

Raising $0$ to any positive power yields $0$ .

$0 + y - 1 = 0$

Add $0$ and $y$ .

$y - 1 = 0$

Add $1$ to both sides of the equation.

$y = 1$

y-intercept(s) in point form.

y-intercept(s): $(0, 1)$

Step 3

List the intersections.

x-intercept(s): $(1, 0), (- 1, 0)$

y-intercept(s): $(0, 1)$

Step 4