Find the x and y Intercepts (-x-3)(-x-4)=y

$(- x - 3) (- x - 4) = y$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$(- x - 3) (- x - 4) = 0$

Solve the equation.

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$- x - 3 = 0$

$- x - 4 = 0$

Set $- x - 3$ equal to $0$ and solve for $x$ .

Set $- x - 3$ equal to $0$ .

$- x - 3 = 0$

Solve $- x - 3 = 0$ for $x$ .

Add $3$ to both sides of the equation.

$- x = 3$

Divide each term in $- x = 3$ by $- 1$ and simplify.

Divide each term in $- x = 3$ by $- 1$ .

$\frac{- x}{- 1} = \frac{3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{3}{- 1}$

Divide $x$ by $1$ .

$x = \frac{3}{- 1}$

Simplify the right side.

Divide $3$ by $- 1$ .

$x = - 3$

Set $- x - 4$ equal to $0$ and solve for $x$ .

Set $- x - 4$ equal to $0$ .

$- x - 4 = 0$

Solve $- x - 4 = 0$ for $x$ .

Add $4$ to both sides of the equation.

$- x = 4$

Divide each term in $- x = 4$ by $- 1$ and simplify.

Divide each term in $- x = 4$ by $- 1$ .

$\frac{- x}{- 1} = \frac{4}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{4}{- 1}$

Divide $x$ by $1$ .

$x = \frac{4}{- 1}$

Simplify the right side.

Divide $4$ by $- 1$ .

$x = - 4$

The final solution is all the values that make $(- x - 3) (- x - 4) = 0$ true.

$x = - 3, - 4$

x-intercept(s) in point form.

x-intercept(s): $(- 3, 0), (- 4, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$(- (0) - 3) (- (0) - 4) = y$

Solve the equation.

Rewrite the equation as $y = (- (0) - 3) (- (0) - 4)$ .

$y = (- (0) - 3) (- (0) - 4)$

Simplify $(- (0) - 3) (- (0) - 4)$ .

Multiply $- 1$ by $0$ .

$y = (0 - 3) (- (0) - 4)$

Subtract $3$ from $0$ .

$y = - 3 (- (0) - 4)$

Multiply $- 1$ by $0$ .

$y = - 3 (0 - 4)$

Subtract $4$ from $0$ .

$y = - 3 \cdot - 4$

Multiply $- 3$ by $- 4$ .

$y = 12$

y-intercept(s) in point form.

y-intercept(s): $(0, 12)$

Step 3

List the intersections.

x-intercept(s): $(- 3, 0), (- 4, 0)$

y-intercept(s): $(0, 12)$

Step 4

Find the x and y Intercepts (-x-3)(-x-4)=y

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