Find the x and y Intercepts (x+3)y=14

$(x + 3) y = 14$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$(x + 3) (0) = 14$

Solve the equation.

Multiply $x + 3$ by $0$ .

$0 = 14$

Since $0 \neq 14$ , there are no solutions.

No solution

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

x-intercept(s): $None$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$((0) + 3) \cdot y = 14$

Solve the equation.

Add $0$ and $3$ .

$3 \cdot y = 14$

Divide each term in $(3 \cdot y) = 14$ by $3$ and simplify.

Divide each term in $(3 \cdot y) = 14$ by $3$ .

$\frac{(3 \cdot y)}{3} = \frac{14}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 \cdot y}{3} = \frac{14}{3}$

Divide $y$ by $1$ .

$y = \frac{14}{3}$

y-intercept(s) in point form.

y-intercept(s): $(0, \frac{14}{3})$

Step 3

List the intersections.

x-intercept(s): $None$

y-intercept(s): $(0, \frac{14}{3})$

Step 4