Find the x and y Intercepts x+3y=-9

$x + 3 y = - 9$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$x + 3 (0) = - 9$

Simplify $x + 3 (0)$ .

Multiply $3$ by $0$ .

$x + 0 = - 9$

Add $x$ and $0$ .

$x = - 9$

x-intercept(s) in point form.

x-intercept(s): $(- 9, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$(0) + 3 y = - 9$

Solve the equation.

Add $0$ and $3 y$ .

$3 y = - 9$

Divide each term in $3 y = - 9$ by $3$ and simplify.

Divide each term in $3 y = - 9$ by $3$ .

$\frac{3 y}{3} = \frac{- 9}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 9}{3}$

Divide $y$ by $1$ .

$y = \frac{- 9}{3}$

Simplify the right side.

Divide $- 9$ by $3$ .

$y = - 3$

y-intercept(s) in point form.

y-intercept(s): $(0, - 3)$

Step 3

List the intersections.

x-intercept(s): $(- 9, 0)$

y-intercept(s): $(0, - 3)$

Step 4