Find the x and y Intercepts x/4-y/3=1

$\frac{x}{4} - \frac{y}{3} = 1$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$\frac{x}{4} - \frac{0}{3} = 1$

Solve the equation.

Simplify $\frac{x}{4} - \frac{0}{3}$ .

Divide $0$ by $3$ .

$\frac{x}{4} - 0 = 1$

Subtract $0$ from $\frac{x}{4}$ .

$\frac{x}{4} = 1$

Multiply both sides of the equation by $4$ .

$4 \frac{x}{4} = 4 \cdot 1$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$4 \frac{x}{4} = 4 \cdot 1$

Rewrite the expression.

$x = 4 \cdot 1$

Simplify the right side.

Multiply $4$ by $1$ .

$x = 4$

x-intercept(s) in point form.

x-intercept(s): $(4, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$\frac{0}{4} - \frac{y}{3} = 1$

Solve the equation.

Combine the opposite terms in $\frac{0}{4} - \frac{y}{3}$ .

Divide $0$ by $4$ .

$0 - \frac{y}{3} = 1$

Subtract $\frac{y}{3}$ from $0$ .

$- \frac{y}{3} = 1$

Multiply both sides of the equation by $- 3$ .

$- 3 (- \frac{y}{3}) = - 3 \cdot 1$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 3 (- \frac{y}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{y}{3}$ into the numerator.

$- 3 \frac{- y}{3} = - 3 \cdot 1$

Factor $3$ out of $- 3$ .

$3 (- 1) \frac{- y}{3} = - 3 \cdot 1$

Cancel the common factor.

$3 \cdot - 1 \frac{- y}{3} = - 3 \cdot 1$

Rewrite the expression.

$- - y = - 3 \cdot 1$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 y = - 3 \cdot 1$

Multiply $y$ by $1$ .

$y = - 3 \cdot 1$

Simplify the right side.

Multiply $- 3$ by $1$ .

$y = - 3$

y-intercept(s) in point form.

y-intercept(s): $(0, - 3)$

List the intersections.

x-intercept(s): $(4, 0)$

y-intercept(s): $(0, - 3)$

Find the x and y Intercepts x/4-y/3=1

Related Questions

Support LCMGCF.com by disabling your adblocker.