Find the x and y Intercepts x=- square root of y

$x = - \sqrt{y}$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$x = - \sqrt{0}$

Simplify $- \sqrt{0}$ .

Remove parentheses.

$x = - \sqrt{0}$

Rewrite $0$ as $0^{2}$ .

$x = - \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = - 0$

Multiply $- 1$ by $0$ .

$x = 0$

x-intercept(s) in point form.

x-intercept(s): $(0, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$0 = - \sqrt{y}$

Solve the equation.

Rewrite the equation as $- \sqrt{y} = 0$ .

$- \sqrt{y} = 0$

To remove the radical on the left side of the equation, square both sides of the equation.

${(- \sqrt{y})}^{2} = 0^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{y}$ as $y^{\frac{1}{2}}$ .

${(- y^{\frac{1}{2}})}^{2} = 0^{2}$

Simplify the left side.

Simplify ${(- y^{\frac{1}{2}})}^{2}$ .

Apply the product rule to $- y^{\frac{1}{2}}$ .

${(- 1)}^{2} {(y^{\frac{1}{2}})}^{2} = 0^{2}$

Raise $- 1$ to the power of $2$ .

$1 {(y^{\frac{1}{2}})}^{2} = 0^{2}$

Multiply ${(y^{\frac{1}{2}})}^{2}$ by $1$ .

${(y^{\frac{1}{2}})}^{2} = 0^{2}$

Multiply the exponents in ${(y^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$y^{\frac{1}{2} \cdot 2} = 0^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$y^{\frac{1}{2} \cdot 2} = 0^{2}$

Rewrite the expression.

$y^{1} = 0^{2}$

Simplify.

$y = 0^{2}$

Simplify the right side.

Raising $0$ to any positive power yields $0$ .

$y = 0$

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

Step 3

List the intersections.

x-intercept(s): $(0, 0)$

y-intercept(s): $(0, 0)$

Step 4

Find the x and y Intercepts x=- square root of y

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