Find the x and y Intercepts y=-1/2x-3

$y = - \frac{1}{2} x - 3$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - \frac{1}{2} x - 3$

Solve the equation.

Rewrite the equation as $- \frac{1}{2} x - 3 = 0$ .

$- \frac{1}{2} x - 3 = 0$

Combine $x$ and $\frac{1}{2}$ .

$- \frac{x}{2} - 3 = 0$

Add $3$ to both sides of the equation.

$- \frac{x}{2} = 3$

Multiply both sides of the equation by $- 2$ .

$- 2 (- \frac{x}{2}) = - 2 \cdot 3$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 2 (- \frac{x}{2})$ .

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{x}{2}$ into the numerator.

$- 2 \frac{- x}{2} = - 2 \cdot 3$

Factor $2$ out of $- 2$ .

$2 (- 1) \frac{- x}{2} = - 2 \cdot 3$

Cancel the common factor.

$2 \cdot - 1 \frac{- x}{2} = - 2 \cdot 3$

Rewrite the expression.

$- - x = - 2 \cdot 3$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - 2 \cdot 3$

Multiply $x$ by $1$ .

$x = - 2 \cdot 3$

Simplify the right side.

Multiply $- 2$ by $3$ .

$x = - 6$

x-intercept(s) in point form.

x-intercept(s): $(- 6, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - \frac{1}{2} \cdot 0 - 3$

Solve the equation.

Remove parentheses.

$y = - \frac{1}{2} \cdot 0 - 3$

Simplify $- \frac{1}{2} \cdot 0 - 3$ .

Multiply $- \frac{1}{2} \cdot 0$ .

Multiply $0$ by $- 1$ .

$y = 0 (\frac{1}{2}) - 3$

Multiply $0$ by $\frac{1}{2}$ .

$y = 0 - 3$

Subtract $3$ from $0$ .

$y = - 3$

y-intercept(s) in point form.

y-intercept(s): $(0, - 3)$

List the intersections.

x-intercept(s): $(- 6, 0)$

y-intercept(s): $(0, - 3)$

Find the x and y Intercepts y=-1/2x-3

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