Find the x and y Intercepts y=-2x^2

$y = - 2 x^{2}$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - 2 x^{2}$

Solve the equation.

Rewrite the equation as $- 2 x^{2} = 0$ .

$- 2 x^{2} = 0$

Divide each term in $- 2 x^{2} = 0$ by $- 2$ and simplify.

Divide each term in $- 2 x^{2} = 0$ by $- 2$ .

$\frac{- 2 x^{2}}{- 2} = \frac{0}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x^{2}}{- 2} = \frac{0}{- 2}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{0}{- 2}$

Simplify the right side.

Divide $0$ by $- 2$ .

$x^{2} = 0$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{0}$

Simplify $\pm \sqrt{0}$ .

Rewrite $0$ as $0^{2}$ .

$x = \pm \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 0$

Plus or minus $0$ is $0$ .

$x = 0$

x-intercept(s) in point form.

x-intercept(s): $(0, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - 2 {(0)}^{2}$

Solve the equation.

Remove parentheses.

$y = - 2 \cdot 0^{2}$

Remove parentheses.

$y = - 2 {(0)}^{2}$

Simplify $- 2 {(0)}^{2}$ .

Raising $0$ to any positive power yields $0$ .

$y = - 2 \cdot 0$

Multiply $- 2$ by $0$ .

$y = 0$

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

List the intersections.

x-intercept(s): $(0, 0)$

y-intercept(s): $(0, 0)$

Find the x and y Intercepts y=-2x^2

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