Find the x and y Intercepts y=3/4x+1

$y = \frac{3}{4} x + 1$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{3}{4} x + 1$

Solve the equation.

Rewrite the equation as $\frac{3}{4} x + 1 = 0$ .

$\frac{3}{4} x + 1 = 0$

Combine $\frac{3}{4}$ and $x$ .

$\frac{3 x}{4} + 1 = 0$

Subtract $1$ from both sides of the equation.

$\frac{3 x}{4} = - 1$

Multiply both sides of the equation by $\frac{4}{3}$ .

$\frac{4}{3} \cdot \frac{3 x}{4} = \frac{4}{3} \cdot - 1$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{3} \cdot \frac{3 x}{4}$ .

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4}{3} \cdot \frac{3 x}{4} = \frac{4}{3} \cdot - 1$

Rewrite the expression.

$\frac{1}{3} (3 x) = \frac{4}{3} \cdot - 1$

Cancel the common factor of $3$ .

Factor $3$ out of $3 x$ .

$\frac{1}{3} (3 (x)) = \frac{4}{3} \cdot - 1$

Cancel the common factor.

$\frac{1}{3} (3 x) = \frac{4}{3} \cdot - 1$

Rewrite the expression.

$x = \frac{4}{3} \cdot - 1$

Simplify the right side.

Simplify $\frac{4}{3} \cdot - 1$ .

Multiply $\frac{4}{3} \cdot - 1$ .

Combine $\frac{4}{3}$ and $- 1$ .

$x = \frac{4 \cdot - 1}{3}$

Multiply $4$ by $- 1$ .

$x = \frac{- 4}{3}$

Move the negative in front of the fraction.

$x = - \frac{4}{3}$

x-intercept(s) in point form.

x-intercept(s): $(- \frac{4}{3}, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{3}{4} \cdot (0) + 1$

Solve the equation.

Multiply $\frac{3}{4}$ by $0$ .

$y = \frac{3}{4} \cdot 0 + 1$

Remove parentheses.

$y = \frac{3}{4} \cdot (0) + 1$

Simplify $\frac{3}{4} \cdot (0) + 1$ .

Multiply $\frac{3}{4}$ by $0$ .

$y = 0 + 1$

Add $0$ and $1$ .

$y = 1$

y-intercept(s) in point form.

y-intercept(s): $(0, 1)$

List the intersections.

x-intercept(s): $(- \frac{4}{3}, 0)$

y-intercept(s): $(0, 1)$

Find the x and y Intercepts y=3/4x+1

Related Questions

Support LCMGCF.com by disabling your adblocker.