Find the x and y Intercepts y=4-2x

$y = 4 - 2 x$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = 4 - 2 x$

Solve the equation.

Rewrite the equation as $4 - 2 x = 0$ .

$4 - 2 x = 0$

Subtract $4$ from both sides of the equation.

$- 2 x = - 4$

Divide each term in $- 2 x = - 4$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 4$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 4}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 4}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 4}{- 2}$

Simplify the right side.

Divide $- 4$ by $- 2$ .

$x = 2$

x-intercept(s) in point form.

x-intercept(s): $(2, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = 4 - 2 \cdot 0$

Solve the equation.

Remove parentheses.

$y = 4 - 2 \cdot 0$

Simplify $4 - 2 \cdot 0$ .

Multiply $- 2$ by $0$ .

$y = 4 + 0$

Add $4$ and $0$ .

$y = 4$

y-intercept(s) in point form.

y-intercept(s): $(0, 4)$

List the intersections.

x-intercept(s): $(2, 0)$

y-intercept(s): $(0, 4)$